By Windler J.

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11(c) we find that the component of VA due to the 2 A source is 160/21 V. 11(d) we find that the component of VA due to the 4 A source is –80/7 V. 11(a) by adding those components to get –320/21 V, the same result we achieved by systematic analysis. ’ Each has advantages. Systematic analysis has the advantage that one only needs to follow some well-defined steps, hopefully minimizing the likelihood of error. Superposition may offer, in some circumstances, the possibility of analysing a small number of simple circuits.

4 k I=? 2 k 6V V =? 2 k V =? V =? (m) (n) (o) (p) 5 mA I=? I =? 6V V =? 3V V =? V=? 7 k I=? 2 k I =? 1 (s) (t) V =? 2. Calculate: (a) the current I through the resistor; and (b) the current I * through the voltage source. If the connection of the current source is now reversed and its value changed to 10 mA, what are the new values of I and I ∗? 3. Calculate: (a) the voltage V across the resistor: and (b) the voltage V ∗ across the current source. If the connection of the voltage source is reversed, what are the new values of V and V *?

To find those voltages we could use systematic analysis 20 times, but that would take a great deal of effort. 12b) a voltage source VOC in series with a resistor RO . 12 A linear circuit N can be represented by a Thevenin equivalent circuit consisting of a voltage source and a resistor calculation 20 times. The new ‘box’ containing VOC and RO is called the Thevenin equivalent of the circuit N. The only question that remains, of course, is how to find the values of VOC and RO . Two calculations are involved, as described below, and are immediately illustrated by an example.